Problema Solution
The sum of three numbers is 136. The third number is 4 times the first. The second number is 10 more than the first. What are the numbers?
Answer provided by our tutors
let the numbers be x, y and z
the sum of three numbers is 136
x + y + z = 136
the third number is 4 times the first
z = 4x
the second number is 10 more than the first.
y = x + 10
by solving the system of equations
x + y + z = 136
z = 4x
y = x + 10
we find
x = 21
y = 31
z = 84
click here to see the step by step solution of the system of equations
the numbers are 21, 31 and 84.