Every even integer can be written in a form 2k, where k is integer thus

two consecutive even integers can be written as: 2k and 2k + 2, where k is integer

the product of the two consecutive even integers is 528

2k(2k + 2) = 528

by simplifying and solving we find 2 roots

k1 = 11

k2 = -12

click here to see the step by step solution of the equations

Click to see all the steps

for k = 11 the two consecutive even integers are 22 and 24

indeed 22*24 = 528

for k = -12 the two consecutive even integers are -24 and -22

indeed (-22)*(-24) = 528

thus we have 2 solutions: the numbers 22 and 24 and the numbers -22 and -24.