Problema Solution

in a certain fraction, when 3 is added to both its numerator and denominator. its value is decreased by 9/10. But when subtracted its value is increased by 9/10. find the denominator of the original fraction

Answer provided by our tutors

let the fraction be


p/q, where p and q are integers and q<>0


that is p is the numerator and q is the denominator


when 3 is added to both its numerator and denominator its value is decreased by 9/10


(p + 3)/ (q + 3) = p/q - 9/10


(p + 3)/ (q + 3) = (10p - 9q)/(10q)


(p + 3)10q = (10p - 9q)(q + 3)


10pq + 30q = 10pq + 30p - 9q^2 - 27q


- 9q^2 - 57q + 30p = 0


But when subtracted its value is increased by 9/10


(p - 3)/ (q - 3) = p/q + 9/10


(p - 3)/ (q - 3) = (10p + 9q)/(10q)


(p - 3)10q = (10p + 9q)(q - 3)


10pq - 30q = 10pq - 10p + 9q^2 - 27q


9q^2 + 3q - 10p = 0


by solving the system


- 9q^2 - 57q + 30p = 0

9q^2 + 3q - 10p = 0


we find


p = 7.2


q = 2.6667


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since the solutions are not integers follows the problem has no solutions - there is no such fraction.