Problema Solution
in a certain fraction, when 3 is added to both its numerator and denominator. its value is decreased by 9/10. But when subtracted its value is increased by 9/10. find the denominator of the original fraction
Answer provided by our tutors
let the fraction be
p/q, where p and q are integers and q<>0
that is p is the numerator and q is the denominator
when 3 is added to both its numerator and denominator its value is decreased by 9/10
(p + 3)/ (q + 3) = p/q - 9/10
(p + 3)/ (q + 3) = (10p - 9q)/(10q)
(p + 3)10q = (10p - 9q)(q + 3)
10pq + 30q = 10pq + 30p - 9q^2 - 27q
- 9q^2 - 57q + 30p = 0
But when subtracted its value is increased by 9/10
(p - 3)/ (q - 3) = p/q + 9/10
(p - 3)/ (q - 3) = (10p + 9q)/(10q)
(p - 3)10q = (10p + 9q)(q - 3)
10pq - 30q = 10pq - 10p + 9q^2 - 27q
9q^2 + 3q - 10p = 0
by solving the system
- 9q^2 - 57q + 30p = 0
9q^2 + 3q - 10p = 0
we find
p = 7.2
q = 2.6667
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since the solutions are not integers follows the problem has no solutions - there is no such fraction.