Problema Solution
a pool measuring 16 meters by 26 meters is surrounded by a path uniform width. If the area of the pool and path combined is 936 square meters. what is the width of the path?
Answer provided by our tutors
let
w be the weight of the path, w>0
then the area of the pool and path combined is the area rectangle with length = 26 + 2w and width = 16 + 2w that is
(26 + 2w)(16 + 2w) = 936
by simplifying and solving the quadratic equation we find and consider only the positive real roots (w>0)
w = 5 m
click here to see the step by step solution of the equation
indeed
(26 + 2*5)(16 + 2*5) = 36+26 = 936 m^2
the width of the path is 5 meters.