Problema Solution

A rope 116 inches long is cut into three pieces. The middle sized piece is 10 inches shorter than twice the shortest piece. The longest piece is 5/3 as long as the shortest piece. What is the length of the shortest piece?

Answer provided by our tutors

let x, y, and z are the 3 pieces that the rope is cut into and let x<y<z


x + y + z = 116


the middle sized piece is 10 inches shorter than twice the shortest piece.


y = 2x - 10


the longest piece is 5/3 as long as the shortest piece


z = 5x/3


by solving the system of equations


x + y + z = 116

y = 2x - 10

z = 5x/3


we find


x = 27 in


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another way of solving is by plugin y = 2x - 10 and z = 5x/3 into x + y + z = 116


x + 2x - 10 + 5x/3 = 116


by solving the equation we find the same solution x = 27 in


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the shortest piece is 27 inches long.