Problema Solution
The sum of three consecutive integers is 108. Find the smallest integer.
Answer provided by our tutors
let the 3 consecutive integers be
x - 1, x, x + 1
where x is integer
the sum of three consecutive integers is 108 thus
x - 1 + x + x + 1 = 108
by simplifying and solving we find
x = 36
the numbers are
x - 1 = 35
x = 36
x + 1 = 37
the smallest integer is 35.