Problema Solution

The sum of three consecutive integers is 108. Find the smallest integer.

Answer provided by our tutors

let the 3 consecutive integers be


x - 1, x, x + 1


where x is integer


the sum of three consecutive integers is 108 thus


x - 1 + x + x + 1 = 108


by simplifying and solving we find


x = 36


the numbers are


x - 1 = 35


x = 36


x + 1 = 37


the smallest integer is 35.