Problema Solution
On a given 530 mile trip an SUV averaged 65mph during the first part and 35 mph during the second part. The total time of the trip was 10 hours. In how much time is each part of the trip?
Answer provided by our tutors
let
d = 530 miles the distance traveled
v1 = 65 mph the average speed on the first part
t1 = the time spent traveling the first part
v2 = 35 mph the average speed on the second part
t2 = the time spent traveling the second part
the total time of the trip was 10 hours.
t1 + t2 = 10
since speed = distance/time => distance = speed*time
v1^t1 + v2*t2 = d
65t1 + 35t2 = 530
by solving the system of equations
t1 + t2 = 10
65t1 + 35t2 = 530
we find
t1 = 6 h
t2 = 4 h
click here to see the step by step solution of the system of equations
the first part of the trip took 6 hours and the second 4 hours.