Problema Solution
Find the equation of the perpendicular bisector of the line joining the points(3,8)and(2,-5)
Answer provided by our tutors
First thing to do is find the coordinates of the mid-point of line segment . That is because the perpendicular bisector of the line segment intersects the line segment at the mid-point by definition of a perpendicular bisector.
midpoint formula:
xo = (x1 + x2)/2
yo = ( y1 + y2)/2
where x1 = 3, y1 = 8, x2 = 2, y2 = -5
xo = 2.5
yo = 1.5
the midpoint is (2.5, 1.5)
Next we need the slope, m, of the given line that contains the line segment:
m = (y1 - y2)/(x1 - x2)
m = (8 -(-5))/(3-2)
m = 13
The slope of a perpendicular is the negative reciprocal of the slope of the given line, that is:
m1 = -1/m
m1 = -1/13
the perpendicular bisector can be written as y = -x/13 + b
since the midpoint (2.5, 1.5) lies on y = -x/13 + b we have
1.5 = -2.5/13 + b
b = 1.5 + 2.5/13
b = 22/13
thus the equation of the perpendicular bisector of the line joining the points (3,8) and (2,-5) is
y = -x/13 + 22/13