Problema Solution

Find the equation of the perpendicular bisector of the line joining the points(3,8)and(2,-5)

Answer provided by our tutors

First thing to do is find the coordinates of the mid-point of line segment . That is because the perpendicular bisector of the line segment intersects the line segment at the mid-point by definition of a perpendicular bisector.


midpoint formula:


xo = (x1 + x2)/2


yo = ( y1 + y2)/2


where x1 = 3, y1 = 8, x2 = 2, y2 = -5


xo = 2.5


yo = 1.5


the midpoint is (2.5, 1.5)


Next we need the slope, m, of the given line that contains the line segment:


m = (y1 - y2)/(x1 - x2)


m = (8 -(-5))/(3-2)


m = 13


The slope of a perpendicular is the negative reciprocal of the slope of the given line, that is:


m1 = -1/m


m1 = -1/13


the perpendicular bisector can be written as y = -x/13 + b


since the midpoint (2.5, 1.5) lies on y = -x/13 + b we have


1.5 = -2.5/13 + b


b = 1.5 + 2.5/13


b = 22/13


thus the equation of the perpendicular bisector of the line joining the points (3,8) and (2,-5) is


y = -x/13 + 22/13