Problema Solution

the length of a rectangle is 3cm less than twice its width. the area of the rectangle is 20 square cm. find the dimensions

Answer provided by our tutors

let


l = the length of the rectangle, l>0

w = the width of the rectangle, w>0


the length of a rectangle is 3cm shorter than twice the width


l = 2w - 3


the area of the rectangle is 20cm


l*w = 20


plug l = 2w - 3 in the above equation


(2w - 3)w = 20


by solving the quadratic equation


(2w - 3)w = 20


we find and consider the positive roots only since w>0


w = 4 cm


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l = 2w - 3 = 2*4 - 3 = 5 cm


the dimensions of the rectangle are 5 cm and 4 cm.