Problema Solution
What is the equation of a line that passes through points (-5,5) and (6,-2)?
Answer provided by our tutors
y = mx + b, m is the slope, b is the y-intercept
lets find the slope m
m = (-2-5)/(6-(-5))
m = -7/11
y = -7x/11 + b
lets find b the y-intercept
the lines goes trough (-5,5) thus
5 = -7*(-5)/11 + b
b = 20/11
the equation of the line trough (-5,5) and (6,-2) is
y = -7x/11 + 20/11