Problema Solution

What is the equation of a line that passes through points (-5,5) and (6,-2)?

Answer provided by our tutors

y = mx + b, m is the slope, b is the y-intercept


lets find the slope m


m = (-2-5)/(6-(-5))


m = -7/11


y = -7x/11 + b


lets find b the y-intercept


the lines goes trough (-5,5) thus


5 = -7*(-5)/11 + b


b = 20/11


the equation of the line trough (-5,5) and (6,-2) is


y = -7x/11 + 20/11