Problema Solution
find the dimension of a rectangular lot whose perimeter is 40 meters and whose area is 96 square meters
Answer provided by our tutors
let
w = the width of the rectangular lot, w>0
l = the length of the rectangular lot, l>0
perimeter is 40 meters
2(l + w) = 40
area is 96 square meters
l*w = 96
l = 96/w
plug l = 96/w into 2(l + w) = 40 we get
2(96/w + w) = 40 divide both sides by 2
96/w + w = 20
by solving we find 2 roots
w1 = 12 m
w2 = 8 m
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for w = 12 m we have l = 96/12 = 8 m
for w = 8 we have l = 96/8 = 12 m
thus the dimensions of the rectangular lot are 12 m and 8 m.