Problema Solution
one third of the sum of two consecutive odd integers is 5 less then the smaller integer. What is the larger integer?
Answer provided by our tutors
Every odd number can be written in a form 2k +1, where k is integer.
Thus the two consecutive odd integers can be written as
2k - 1, 2k + 1, where k is integer
and let 2k + 1 > 2k - 1
one third of the sum of two consecutive odd integers is 5 less then the smaller integer
(2k -1 + 2k + 1)/3 = 2k - 1 - 5
by solving we find
k = 9
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the larger number is 2k + 1 = 2*9 + 1 = 19
the larger number is 19.