Problema Solution

A rectange is twice as long as it is wide. It's area is 72. What is its perimiter?

Answer provided by our tutors

let


l = the length of the rectangle, l>0

w = the width of the rectangle, w>0


A rectange is twice as long as it is wide


l = 2w


It's area is 72


l*w = 72


plug l = 2w into the last equation


2w*w = 72


by solving the quadratic equation we find


w = 6


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l = 2*w = 2*6 = 12


the perimeter of rectangle is P = 2(l + w)


P = 2(12 + 6)


P = 36


the perimeter is 36.