Problema Solution
A stadium has 49,000 seats. Seats sell for $25 in section A, $20 in section B, and $15 in section C. The number of seats in section A equals the total number of seats in section B and C. Suppose the stadium takes in $1,052,000 from each sold-out event. How many seats would each section hold?
Answer provided by our tutors
let
a = the number of seats in section A
b = the number of seats in section B
c = the number of seats in section C
stadium has 49,000 seats
a + b + c = 49000
the number of seats in section A equals the total number of seats in section B and C
a = b + c
the stadium takes in $1,052,000 from each sold-out event
25a + 20b + 15c = 1052000
by solving the system of equations
a + b + c = 49000
a = b + c
25a + 20b + 15c = 1052000
we find
a = 24,500 seats
b = 14,400 seats
c = 10,100 seats
click here to see the step by step solution of the system of equations
section A has 24,500 seats.
section B has 14,400 seats.
section C has 10,100 seats.