Problema Solution
Two cars are 206 miles apart and traveing toward each other. One car travels 7 mph faster than the other car. The cars meet in 2 hour. Find the speed of the faster car.
Answer provided by our tutors
let 'v' represent the velocity of the slower car, then 'v+7' represents the velocity of the faster car, in mph
let 'd' represent the distance travelled by the slower car, then '206-d' represents the distance travelled by the faster car, in miles
distance = rate * time
therefore:
time = distance / rate
both cars travelled 2 hours, so we can derive the following equations:
for the slower car:
2 = d / v
for the faster car:
2 = (206-d)/(v+7)
solving this system of equations:
2 = d / v
2 = (206-d)/(v+7)
we have:
d = 96
v = 48
48+7=55
the slower car was travelling at 48 mph, the faster car was travelling at 55 mph