Problema Solution

Susan paid for her library fine with 26 coins consisting of nickels and dimes. If the fine was $2.10, how many coins were nickels?

Answer provided by our tutors

let


n = the number of nickles, n is positive integer

d = the number of dimes, d is positive integer


1 nickle = 5 cents = $0.05

1 dime = 10 cents = $0.1


Susan paid for her library fine with 26 coins consisting of nickels and dimes


n + d = 26


the fine was $2.10


0.05n + 0.1d = 2.10


by solving the system of equations


n + d = 26

0.05n + 0.1d = 2.10


we find


n = 10 nickles


d = 16 dimes


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Susan had 10 nickles.