Problema Solution
a fathers age is twice his daughters age but 16 years ago the fathers age was 4 times his daughters age.calculate their ages
Answer provided by our tutors
let
f = the age of the father
d = the age of the daughter
a fathers age is twice his daughters age
f = 2d
16 years ago the fathers age was 4 times his daughters age
(f - 16) = 4(d - 16)
by solving the system of equations
f = 2d
(f - 16) = 4(d - 16)
we find
f = 48 years
d = 24 years
click here to check the step by step solution of the system
the father is 48 years old.
the daughter is 24 years old.