Problema Solution
The length of a rectangle is 8 yd less than three times the width, and the area of the rectangle is 35 yd^2. Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
the length of a rectangle is 8 yd less than three times the width
l = 3w - 8
the area of the rectangle is 35 yd^2
l*w = 35
plug l = 3w - 8 into l*w = 35
(3w - 8)*w = 35
by solving the equation we find
w = 5 yd
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l = 3w - 8 = 3*5 - 8 = 15 - 8 = 7 yd
the dimensions of the rectangle are 7 yd and 5 yd.