Problema Solution
A pharmacist wishes to mix water with a 15%–saline solution to create 200 mL of 6% saline solution. How much 15%–saline solution must be used?
Answer provided by our tutors
Since it is not given, we will assume that the water has a concentration of 100%. From the given information, we can write:
x(.15)+(200-x)(1)=200(.6)
where 'x' stands for the amount of 15% saline solution needed, '200-x' stands for the amount of water needed, and 200 is the total volume that is desired. Solving for 'x', we get:
x=94.12 mL