Problema Solution
Sarah has a collection of nickels, dimes, and quarters worth $12.50. She has 10 more dimes than nickels and twice as many quarters as dimes. How many coins of each kind does she have?
Answer provided by our tutors
let
n = the number of nickles
d = the number of dimes
q = the number of quarters
1 nickle = $0.05
1 dime = $0.1
1 quarter = $0.25
Sarah has a collection of nickels, dimes, and quarters worth $12.50
0.05n + 0.1d + 0.25q = 12.50
She has 10 more dimes than nickels
d = n + 10
twice as many quarters as dimes
q = 2d
by solving the system of equation
0.05n + 0.1d + 0.25q = 12.50
d = n + 10
q = 2d
we find
n = 10 nickles
d = 20 dimes
q = 40 quarters
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Sarah has 10 nickles, 20 dimes and 40 quarters.