Problema Solution
Find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 70
Answer provided by our tutors
every odd integer can be written as 2k + 1, where k is integer
the 3 consecutive odd integers can be written as:
2k - 1, 2k + 1, 2k + 3
the sum of the first, twice the second, and three times the third is 70
(2k - 1) + 2(2k + 1) + 3(2k + 3) = 70
by solving we find
k = 5
click here to see the step by step solution of the equation
2k - 1 = 2*5 - 1 = 9
2k + 1 = 2*5 + 1 = 11
2k + 3 = 2*5 + 3 = 13
the three consecutive odd integers are 9, 11 and 13.