Problema Solution
5 consecutive integers are added. The sum is 6 more than the greatest of the 5 integers. What was the smallest of the integers?
Answer provided by our tutors
let 5 consecutive integers can be written as
x - 2, x - 1, x , x + 1, x + 2
where x is integer
the greatest number of the six is: x + 2
the smallest number of the six is: x - 2
the sum is 6 more than the greatest of the 5 integers
x - 2 + x - 1 + x + x + 1 + x + 2 = 6 + x + 2
by solving we find
x = 2
click here to see the step by step solution of the equation
x - 2 = 2 - 2 = 0
indeed
0 + 1 + 2 + 3 + 4 = 10 = 6 + 4
the smallest integer is 0.