Problema Solution

if x+y6 , where x and y are integers, what is the largest integral value of xy ?

Answer provided by our tutors

x + y = 6


y = 6 - x


plug y = 6 - x into xy


x(6 - x) = 6x - x^2


we look for the maximum value of the function


f(x) = 6x - x^2


f(x) is parabolic function with negative quotient in front of x^2 that is -1<0 thus it maximum in the vertex


the maximum is calculated by the formula c - b^2/(4a) where a = -1, b = 6 and c = 0


0^2 - 6^2/(4*(-1)) = 36/4 = 9


lets check if x and y are integers


from 6x - x^2 = 9 we find the solution


x = 3 is integer


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y = 6 - x = 6 - 3 = 3 is integer


if we draw the graph we can also see that the function has a maximum equal to 9

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the largest integral value of xy is 9.