Problema Solution

In ∆ABC, a = 3 centimeters, c = 4 centimeters, and m B = 135°. What is AC to two decimal places?

Answer provided by our tutors

let


a = 3 cm

c = 4 cm

mB = 135


we need do find AC = b


according to Low of Cosines we have


b^2 = a^2 + c^2 - 2ac(cos mB)


b^2 = 3^2 + 4^2 - 2*3*4*(cos 135)


by solving the equation we find


b = 6.48 cm


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AC is 6.48 cm.