Problema Solution
Jack's house is 520 m away from Kelly's house. If they started to walk towards each other at the same time, then they will meet after 20 minutes. If Jack can walk 8 meters per minute, what is Kelly's rate?
Answer provided by our tutors
let
d = 520 m the distance between the houses
t = 20 min the time of the walk
v1 = 8 m/min Jacks rate
v2 = Kelly's rate
rate = distance/time => distance = rate*time
v1*t + v2*t = d
8*20 + v2*20 = 520
by solving the equation we find
v2 = 18 meters per min
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Kelly's rate is 18 meters per minute.