Problema Solution
A car left capital city at and average rate of 45 miles per hour. 45 minutes later a second car left capital city and traveled the same route at an average rate of 60 miles per hour. In how many minutes will the second car catch the first?
Answer provided by our tutors
let
v1 = 45 mph the speed of the first car
v2 = 60 mph the speed of the second car
t = the time the second car traveled
t + 45/60 = t + 0.75 the time the first car traveled
since speed = distance/time => distance = time*speed
(t + 0.75)*v1 = t*v2
(t + 0.75)*45 = t*60
by solving the equation we find
t = 2.25 hours = 2.25*60 min = 135 min
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the second car will catch the first in 135 minutes.