Problema Solution
Which of the following is a zero of the function f(x)=x^3-7x^2+2x+40
Answer provided by our tutors
the zeros of the function f(x)=x^3-7x^2+2x+40 are -2, 4 and 5
indeed
f(-2) = (-2)^3-7((-2)^2)+2(-2)+40
f(-2) = 0
f(4)=4^3-7*4^2+2*4+40
f(4) = 0
f(5)=5^3-7*5^2+2*5+40
f(5) = 0