Problema Solution
The manager of a store selling tea plans mix a tea that costs $9 per pound with a less expensive tea that costs $4 per pound to create a 90-pound blend that will sell for $8 per pound. How many pounds of each tea are required?
Answer provided by our tutors
let
x = lbs of the $9 per pound tea
y = lbs of the $4 per pound tea
90-pound blend that will sell for $8 per pound
x + y = 90
9x + 4y = 90*8
by solving the above system of equations we find
x = 72 lbs
y = 18 lbs
click here to see the step by step solution of the system of equations
72 lbs of the $9 per pound tea should be mixed with 18 lbs of the $4 per pound tea.