Problema Solution
The base of a rectangular box has a perimeter of 30 inches, the front of the box has a perimeter of 22 inches, what is the volume of the box?
Answer provided by our tutors
let
w = the width of the box
l = the length of the box
h = the height of the box
the base of a rectangular box has a perimeter of 30 inches
2(l + w) = 30 divide both sides by 2
l + w = 15 => w = 15 - l
the front of the box has a perimeter of 22 inches
2(l + h) = 22 divide both sides by 2
l + h = 11 => h = 11 - l
we need to find the volume V = w*l*h
V = (15 - l)*l*(11 -l)
V = 165l - 15 l^2 - 11l + l^2
V = l^3 - 26 l^2 + 165l
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