Problema Solution
CINDY HAD A BAG OF JELLY BEANS. SHE GAVE HALF OF HER JELLY BEANS TO JAN, AND THEN SHE ATE TWO. SHE GAVE HAVE OF WHAT WAS LEFT TO BOBBY, AND THEN SHE ATE TWO. NEXT, SHE GAVE HALF OF THE REMAINING JELLY BEANS TO MARCIA, AND THEN SHE ATE TWO. CINDY WANTED TO EAT MORE JELLY BEANS BUT THE BAG OF JELLY BEANS WAS NOW EMPTY. HOW MANY JELLY BEANS DID CINDY GIVE AWAY?
Answer provided by our tutors
let x = the total number of jelly beans in the bag
gave to Jan: x/2
Cindy ate: 2
jelly beans left: x/2 - 2
gave to Bobby: 1/2(x/2 - 2) = x/4 - 1
Cindy ate: 2
jelly beans left: x/4 - 1 - 2 = x/4 - 3
gave to Marcia: (1/2)(x/4 - 3) = x/8 - 3/2
Cindy ate: 2
jelly beans left: x/8 - 3/2 - 2 = 0
by solving x/8 - 3/2 - 2 = 0 we find
x = 28
click here to see the step by step solution of the equation
the total number jelly beans that Cindy had in the beginning is 28
total number of jelly beans given away will be
x - (the total number of jelly beans Cindy ate) = 28 - (2 + 2 + 2) = 28 - 6 = 22 jelly beans
Cindy gave away 22 jelly beans.