Problema Solution
a rectangular sign has a perimeter of 96 feet. the length is 3 feet less than twice its width. find the dimensions of the sign
Answer provided by our tutors
let
l = the length of the sign
w= the width of the sign
the length is 3 feet less than twice its width
l = 2w - 3
a rectangular sign has a perimeter of 96 feet
2(l + w) = 96
by solving the system of equations
l = 2w - 3
2(l + w) = 96
we find
l = 31 ft
w = 17 ft
click here to see the step by step solution of the system of equations
the dimensions of the sign are 31 feet and 17 feet.