Problema Solution
A rectangle is twice as long as it is wide. The perimeter is 60 feet. Find the dimensions.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
a rectangle is twice as long as it is wide
l = 2w
the perimeter is 60 feet
2(l + w) = 60
by solving the system of equations
l = 2w
2(l + w) = 60
we find
l = 20 ft
w = 10 ft
click here to see the step by step solution of the system of equations
the dimensions of the rectangle are 20 ft and 10 ft.