Problema Solution

The sum of the squares of two consecutive integers is 181

Answer provided by our tutors

the consecutive integers can be written as


x and x + 1


where x is integer


x^2 + (x + 1)^2 = 181


by solving the equation we find 2 solutions (the quadratic equation has two roots)


x1 = 9


x2 = - 10


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there are 2 solution:


9 and 10 (indeed 9^2 + 10^2 = 181)


-9 and - 10 (indeed (-9)^2 + (-10)^2 = 181)