Problema Solution
Two planes are 2375 mi apart and are traveling toward each other. One plane is traveling 110 mph faster than the other plane. The planes pass each other in 2.5 h. Find the speed of each plane.
Answer provided by our tutors
let the speed of the slower plane be: v
the speed of the 110 mph faster plane will be: v + 110
the time of the travel is: t = 2.5 h
since speed = distance/time => distance = speed*time
the distance of the first plane + the distance of the second plane = 2375 mi (the total distance at the start)
v*t + (v + 110)t = 2375
v*2.5 + (v + 110)2.5 = 2375
by solving we find
v = 420 mph
click here to see the step by step solution of the equation
v + 110 = 420 + 110 = 530 mph
the speed of the first plane is 420 mph.
the speed of the second plane is 530 mph.