Problema Solution
The perimeter of a rectangle is 34ft.. If the lengths were doubled and the widths were increased by 6 ft., the perimeter would be 70 ft. What are the length and width of the rectangle?
Answer provided by our tutors
Length = x
width = y
x + y = 34/2
x + y = 17 ......(1)
2x + y + 6 = 70/2
2x + y = 29 ........(1)
Solving (1) and (2)
x = 12, y = 5
Length = 12 and width = 5