Problema Solution
the first of three numbers exceeds twice the second by 4, while the third number is twice the first. if the sum of the numbers is 54, what are the numbers?
Answer provided by our tutors
let 'x', 'y' and 'x' be the numbers
the first of three numbers exceeds twice the second by 4
x = 2y + 4
the third number is twice the first
z = 2x
the sum of the numbers is 54
x + y + z = 54
by solving the system of equations
x = 2y + 4
z = 2x
x + y + z = 54
we find
x = 16
y = 6
z = 32
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the numbers are 16, 6 and 32.