Problema Solution
The area of a rectangle is 629 cm. If the length of the rectangle is 3 more than twice its width, find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
the length of the rectangle is 3 more than twice its width
l = 3 + 2w
the area of a rectangle is 629 cm^2
l*w = 629
plug l = 3 + 2w into the last equation
(3 + 2w)*w = 629
we find and consider the positive roots (the length can not be a negative number)
w = 17 cm
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l = 3 + 2*17
l = 37 cm
the dimension of the rectangle are 17 cm and 37 cm.