Problema Solution
When Gary and Rowena were married, Rowena was two years younger than Gary. How old was Gray on his wedding day if sixteen years before his wedding he was twice as old as Rowena was then?
Answer provided by our tutors
let
g = the age of Gary
r = the age of Rowena
Rowena was two years younger than Gary
r = g - 2
sixteen years before the wedding Gary was twice as old as Rowena
(g - 16) = 2(r - 16)
by solving the system of equations
r = g - 2
(g - 16) = 2(r - 16)
we find
g = 20 years
r = 18 years
click here to see the step by step solution of the system of equations
Gary was 20 years old on his wedding day.