Problema Solution
Two cyclists start from the same point at the same time and move in opposite directions. Once cyclist is traveling at 14 mph, and the other cyclist is traveling at 12 mph. After 15 min, how far apart are the two cyclists?
Answer provided by our tutors
let
v1 = 14 mph the speed of the first cyclist
v2 = 12 mph the speed of the second cyclist
t = 15 min = 15/60 = 0.25 h the time of the travel
the speed = distance/time follows the distance = speed*time
since the cyclists are traveling in the opposite directions the distance between them d will be equal to the sum of the distance of the first cyclist and the distance of the second cyclist
d = v1*t + v2*t
d = 14*0.25 + 12*0.25
d = 6.5 miles
the two cyclists are 6.5 miles apart.