Problema Solution
Larry, Curly, and Mo assembled a puzzle together in 40 hours. If Curly worked twice as fast as Mo and Larry worked just as fast as Curly, then how long would it have taken Mo to assemble the puzzle alone?
Answer provided by our tutors
let
l = the number of hours that Larry needs to assemble the puzzle alone
c = the number of hours that Curly needs to assemble the puzzle alone
m = the number of hours that Mo needs to assemble the puzzle alone
Curly worked twice as fast as Mo
c = m/2
Larry worked just as fast as Curly
l = c
Larry, Curly, and Mo assembled a puzzle together in 40 hours
1/l + 1/c + 1/m = 1/40
plug c = m/2 and l = m/2 (since l = c) into the last equation
1/(m/2) + 1/(m/2) + 1/m = 1/40
by solving we find
m = 200 h
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It takes 200 hours for Mo the assemble the puzzle alone.