Problema Solution

The length of a rectangle is 1ft more than double the width, and the area of the rectangle is 66ft^2 . Find the dimensions of the rectangle.

Answer provided by our tutors

let


l = the length of the rectangle

w = the width of the rectangle


the length of a rectangle is 1ft more than double the width


l = 1 + 2w


the area of the rectangle is 66ft^2


l*w = 66


we plug l = 1 + 2w into the last equation


(1 + 2w)w = 66


and find and consider the positive root since the width can not be negative number


w = 5.5 ft


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l = 1 + 2*5.5


l = 12 ft


the dimensions of the rectangle are 5.5 feet and 12 feet.