Problema Solution
The length of a rectangle is 1ft more than double the width, and the area of the rectangle is 66ft^2 . Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
the length of a rectangle is 1ft more than double the width
l = 1 + 2w
the area of the rectangle is 66ft^2
l*w = 66
we plug l = 1 + 2w into the last equation
(1 + 2w)w = 66
and find and consider the positive root since the width can not be negative number
w = 5.5 ft
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l = 1 + 2*5.5
l = 12 ft
the dimensions of the rectangle are 5.5 feet and 12 feet.