Problema Solution
A building in a city has rectangular base. The length of base measures 60ft less than twice the width. The perimeter of the base is 840 ft. What are the dimensions of the base?
Answer provided by our tutors
let
l = the length of the rectangular base
w = the width of the rectangular base
the length of base measures 60ft less than twice the width
l = 2w - 60
the perimeter of the base is 840 ft
2(l + w) = 840
by solving the system of equations
l = 2w - 60
2(l + w) = 840
we find
l = 260 ft
w = 160 ft
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the dimensions of the base are 250 ft and 160 ft.