Problema Solution
A newspaper carrier has $3.00. He has 3 more quarters than dimes, but 4 times as many nickles as quarters. How many coins of each type does he have?
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
$3.00 = 300 cents
let
n = the number of nickles
d = the number of dimes
q = the number of quarters
He has 3 more quarters than dimes,
q = d + 3
but 4 times as many nickles as quarters
n = 4q
the total value of all coins is 300 cents
5n + 10d + 25q = 300
by solving the system of equations
q = d + 3
n = 4q
5n + 10d + 25q = 300
we find
n = 24 nickles
d = 3 dimes
q = 6 quarters
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