Problema Solution
Driver 1 starts from A and moves to B with speed of 60 mi/hr.
Driver 2 starts from B two hours later and moves to A with speed of 80 mi/hr.
Distance AB is 540 mi.
How long will it take for them to meet?
Where will it happen?
Answer provided by our tutors
let
v1 = 60 mi/hr the speed of Driver 1
v2 = 80 mi/hr the speed of Driver 2
d = 540 the distance AB
t = the time of the travel
since speed = distance/time => distance = speed*time
v1*t + v2*t = d
60t + 80t = 540
by solving for t we find
t = 27/7
t = 3 6/7 hr
t = 3.86 hr
t = 3 hr (6*60)/7 min
t = 3 hr 51 min 3*60/7 sec
t = 3 hr 51 min 26 sec
click here to see the step by step solution of the equation
it will take them 3.86 hr or 3 hr 51 min 26 sec to meet.
since 60*t = 60*27/7 = 231.43 km
the cars will meet 231.43 km from A.