Problema Solution
How many gallons of a 60% antifreeze solution must be mixed with 17 gallons of 15% if antifreeze to get a mixture that is 50% antifreeze?
Answer provided by our tutors
let x = gal of 60% antifreeze solution
0.60*x + 0.15*17 = 0.50(x + 17)
by solving we find
x = 59.5 gal
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