Problema Solution
Plane a leaves airpot1 and heads to airport 2 which is a distance of 2,700 km. At the same time, plane b leaves airport 2 and heads for airport 1.Due to headwinds and tailwinds, plane a average speed is 100 kph greater than that of plane b. if the two planes pass each other after 3 hours, find the speed of each plane.
Answer provided by our tutors
let
d = 2,700 km the total distance
v1 = the speed of plane a
v2 = the speed of plane b
t = 3 h the time of the travel
Due to headwinds and tailwinds, plane a average speed is 100 kph greater than that of plane b
v1 = 100 + v2
the two planes pass each other after 3 hours
v1*t + v2*t = d
3(v1 + v2) = 2700
by solving the system of equations
v1 = 100 + v2
3(v1 + v2) = 2700
we find
v1 = 500 kph
v2 = 400 kph
click here to see the step by step solution of the system of equations
the speed of plane a is 500 kph.
the speed of plane b is 400 kph.