Problema Solution

A new car worth 24,000 is depreciating in value by 3000 per year. The mathematical model is y= -3000x+24,000

A. Find the x intercept. Describe what this means I terms of the cars value

B. Find the y intercept and describe what this means in terms of the cars value

C. Use the intercepts to graph the linear equatio. Because x and y must be nonnegative (why?), limit your graph to quadrant 1 and it's boundaries

D. Use your graph to estimate the cars value after five years

Answer provided by our tutors

A. Find the x intercept. Describe what this means I terms of the cars value


y= -3000x+24,000


the x intercept happens for y = 0 that is


-3000x+24000 = 0


x = 8 years


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in 8 years the value of the car will be $0.


B. Find the y intercept and describe what this means in terms of the cars value


y= -3000x+24,000


the y intercept happens when x = 0 that is


y= -3000*0+24,000


y = $24000


this means that in the beginning the car value is $24000.


C. Use the intercepts to graph the linear equation. Because x and y must be nonnegative (why?), limit your graph to quadrant 1 and it's boundaries


click here to see the graph

https://www.quickmath.com/webMathematica3/quickmath/graphs/equations/advanced.jsp#c=plot_advancedgraphequations&v1=+y%3D+-3000*x%2B24000+&v7=x&v8=y&v9=0&v10=10&v11=0&v12=25000


x is nonnegative since time can not be negative (we are talking about years in the future)

y is nonnegative since time can not be negative because the value of the car cannot be a negative number.


D. Use your graph to estimate the cars value after five years


y= -3000*5+24,000


y = $9,000