Problema Solution

A perimeter of a rectangle is 42 cm, and the area is 68. Find the length and width of the rectangle

Answer provided by our tutors

let


l = the length of the rectangle

w = the width of the rectangle


the perimeter of the rectangle is 42 cm


2(l + w) = 42 divide both sides by 2


l + w = 21


l = 21 - w


the area is 68 cm^2


l*w = 68


plug l = 21 - w into l*w = 68


(21-w)*w = 68


by solving we find two roots


w1 = 17


w2 = 4


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for w = 17 we have l = 21-17 = 4


for w = 4 we get l = 21-4 = 17


since l>w the solution is l=17 cm and w=4 cm.