Problema Solution
An outboard engine uses a gasoline-oil mixture in the ratio of 15 to 1. How much gasoline must be mixed with a gasoline oil mixture, which is 75% gasoline, to make 8.0L of the mixture?
Answer provided by our tutors
Let x = L of gasoline that must be used for the mix
the percent of gasoline in a 15:1 mixture is
(15/(15+1))* 100 = 93.75% gasoline
75% of gasoline in 8-x + 100% gasoline of x = 93.75% gasoline of the mixture of 8 L
0.75*(8 - x) + 1.00*x = 0.9375*8
by solving we find
x = 6 L
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6 liters of gasoline is required for the 8 L mixture.