Problema Solution
1. Twice the sum of two numbers exceeds three times their difference by 8, while half the sum is one more than the difference. What are the numbers?
Answer provided by our tutors
let 'x' and 'y' be the numbers
twice the sum of two numbers exceeds three times their difference by 8
2(x + y) = 8 + 3(x - y)
half the sum is one more than the difference
(1/2)(x + y) = 1 + (x - y)
by solving the system of equations
2(x + y) = 8 + 3(x - y)
(1/2)(x + y) = 1 + (x - y)
we find
x = 7
y = 3
click here to see the step by step solution of the system of equations
the numbers are 3 and 7.